0.5x^2+5x+5=0

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Solution for 0.5x^2+5x+5=0 equation: 



0.5x^2+5x+5=0

a = 0.5; b = 5; c = +5;
Δ = b2-4ac
Δ = 52-4·0.5·5
Δ = 15
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{15}}{2*0.5}=\frac{-5-\sqrt{15}}{1}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{15}}{2*0.5}=\frac{-5+\sqrt{15}}{1}
$

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